怎样吧x^5-4x+3变成(x-1)乘以另一个公因式的形式
来源:百度知道 编辑:UC知道 时间:2024/06/28 17:08:48
楼上的有错,他的结果=x^5-3x-x^4+3
x^5-4x+3
=X^5-x-(3x-3)
=x^5-x-3(x-1)
=x(x^4-1)-3(x-1)
=x(x^2+1)(x^2-1)-3(x-1)
=x(x^2+1)(x+1)(x-1)-3(x-1)
=(x-1)[x(x^2+1)(x+1)-3]
应该是这样了。。
x^5-4x+3
=x^5-x-(3x-3)
=x(x^4-1)-3(x-1)
=x(x^2+1)(x^2-1)-3(x-1)
=x(x^2+1)(x+1)(x-1)-3(x-1)
=[x(x^2+1)(x+1)-3]*(x-1)
=(x-1)(x^4+x^3+x^2+x-3)
x^5-4x+3
=X^5-x-(3x-3)
=x^5-x-3(x-1)
=x(x^4-1)-3(x-1)
=x(x^2+1)(x^2-1)-3(x-1)
=x(x^2+1)(x+1)(x-1)-3(x-1)
=(x-1)[x(x^2+1)(x+1)-3]
=(x-1)[(x^3+x)(x+1)-3]
=(x-1)(x^4+x^3+x^2+x-3)
x^5-4x+3
=x^5-x-(3x-3)
=x^4(x-1)-3(x-1)
=(x-1)(x^4-3)
x^5-4x+3
=X^5-x-(3x-3)
=x^5-x-3(x-1)
=x(x^4-1)-3(x-1)
=x(x^2-1)(x^2+1)-3(x-1)
=x(x-1)(x+1)(x^2+1)-3(x-1)
=(x-1)[x(x+1)(x^2+1)-3]
公因式?
因式吧?
直接除就找到了,综合除法快点,另一个因式答案:x^4+x^3+x^2+x-3
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